By Bernard Morrill

ISBN-10: 0080171842

ISBN-13: 9780080171845

Answer guide for an creation to Equilibrium Thermodynamics

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**Sample text**

3 ft /sec 3 entity = 3 7 . 3 x 7 . 4 S 1 = 279gaL/sec 7-5 h-«-* = 1260 BTU/lbm p = 410 psia; t 7-2 t„ = 400 F 0 t = 0,0204ft /lbn v v 3 1 = 80 F = 500ft /ibm 0 at 0 = 400osia Sc. 01608 2f w 1 • L S 6 3 3 - x = 500°Fj h = ? 8 BTU/lbm x From equation ( 7 . 4 . 4 ) JIEGL. 7898 v* = J2x32,2(1260 , - 1 2 3 4 3 . 10) (v* _ yf)/2 2 continued continued -J 2 P ^ v dp 38 7-8 cont. 7-6 cont. 5:v*=100 1 1 2 1 For an incompressible flov; alternate solution AT v? 73 2 7-8 „ Referring to the solution oi problem 7-6: For a perfect gas (air) (checks OX ) 7-9 Turbines acts like a throttling device.

N . -^N d|. d^. 32) dL[^ ] = - sdT + vdp -Z. ] = 6-7 [1 Ah = c AT : p = const. 4 BTU = k [S +p 6 6-8 2 1 ^ ] = (1 - ** i / = S - 2 6-10 S = k<3\ + k|3^E> dA = bdB + cdC [X,A] = ^>XdA continued - 1 • • 111 continued • •• • • — (E)] where (j (E) is the variation of (E). ) Then multiply equation by X , with Then the result that Ov, ^ v [X,A] = b[x,B] + c[x,c] T T [P» ] v[p,T] V [ T > V ] [ V f T ] or which has the meaning that ^XdA = b^XdB + c J XdC By multiplying by - 1 , we get & \ - <§f >, T + v & \ all measurable quantities. **

Also, for a r =0, the efficiency is THER • -cT(r p 1 P -1) D I F F E R E N T I A T E WITH R E S P E C T TO r SET TO S E R O : P snd di? 1/Or P 1 P = (T /T ) P 3 1 r ODTL^IUM R P IS ir-i/t) - 1 -T r #2(r-i) QED THE C O N D I T I O N OF iTtaxirnuia V/ORLC OUTPUT. 7er) 0 « T_r 3p A L S O Z E R O . 1 h. 446 h. w. 0932 **£ without pump work B p*W. w. 2 . 5 4 500 1-h_ = v. I ^0,5069 continued 2 1 47 8-18 cont. h -h 2 8-19 cont. 507 . 3£ = 38. RR 8-19 T A slight increase 8-20 work =w - w net «j> p (h T = 700 F 3 T = 700°F.

### Solution Manual for an Introduction to Equilibrium Thermodynamics by Bernard Morrill

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